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0 votes1 answer181 views4 Years Ago
Modified 4 Year Ago
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0 votes1 answer164 viewsIndrani 4 Years Ago
Chemical Reactions With Very High Ea Values Are Generally
JEE DiscussionsModified 4 Year Ago Indrani
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0 votes1 answer151 views4 Years Ago
The Rate Of Reaction Increases With Temperature Due To
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0 votes1 answer244 views
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0 votes1 answer245 views4 Years Ago
If The Rate Of Reaction A --> B Doubles On Increasing The Concentration Of A By 4 Times, The Order Of The Reaction Is
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0 votes1 answer278 views4 Years Ago
A First Order Reaction Is 10per Complete In 20 Min. The Time Taken For 19er Completion Is
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0 votes1 answer112 views
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0 votes1 answer252 views4 Years Ago
In The First Order Reaction, The Concentration Of The Reactants Is Reduced To 25 Per In One Hour. The Half-life Period Of The Reaction Is
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0 votes1 answer167 views4 Years Ago
A Reaction Involving Two Different Reactants Can Never Be
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0 votes1 answer272 views4 Years Ago
Modified 4 Year Ago
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0 votes1 answer122 views
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0 votes1 answer196 views4 Years Ago
For A First Order Reaction With Rate Constant K And Initial Concentration A , The Half-life Period Is Given By
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0 votes1 answer228 views4 Years Ago
Modified 4 Year Ago
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0 votes1 answer199 views
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0 votes1 answer243 views4 Years Ago
1/[A]^2 Versus Time Is Straight Line. Order Of Reaction Is
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0 votes1 answer260 views4 Years Ago
For A Reaction, The Rate Constant Is 2.34 S^-1. The Half-life Period For The Reaction Is
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0 votes1 answer267 views4 Years Ago
A Reaction Proceeds By First Order, 75 Per Of This Reaction Was Completed In 32 Min. The Time Required For 50 Per Completion Is
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0 votes1 answer291 views4 Years Ago
A First Order Reaction Is 60 Per Complete In 20 Min. How Long Will The Reaction Take To Be 84 Per Complete?
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0 votes1 answer312 views4 Years Ago
For A First Order Reaction The Ratio Of Times To Complete 99.9 Per. And Half Of The Reaction Is
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0 votes1 answer246 views4 Years Ago
The Half-life Of A Reaction Is Halved As The Initial Concentration Of The Reactant Is Doubled. The Order Of The Reaction Is
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0 votes1 answer190 views
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0 votes1 answer178 views